(3p-4)^2=-6(3p-4)+16

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Solution for (3p-4)^2=-6(3p-4)+16 equation: 



(3p-4)^2=-6(3p-4)+16

We move all terms to the left:

(3p-4)^2-(-6(3p-4)+16)=0



We calculate terms in parentheses: -(-6(3p-4)+16), so:

-6(3p-4)+16

We multiply parentheses

-18p+24+16

We add all the numbers together, and all the variables

-18p+40

Back to the equation:

-(-18p+40)



We get rid of parentheses

(3p-4)^2+18p-40=0

We add all the numbers together, and all the variables

18p+(3p-4)^2-40=0

We move all terms containing p to the left, all other terms to the right

18p+(3p-4)^2=40

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